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Richard Mitnick
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timing and work in Rice

I am trying to make sense of the timing and work in Rice. If one has up the graphic, one can see the progress in two thermometers:
"work unit" [wu], which is the totality, and "next structure" [ns].

On a dual core, each ns took about 1.75 minutes, and completed .22% of the wu. So, that means, 100%wu/.22wu= 454.54 ns's. so, 454 X 1.75=794.5 minutes, or 13.24 hours.

On a PIII each ns took 5.66 minutes and completed 1.11% of the wu, so 90.09 ns , so 90.09 X 5.4=486.48 minutes, or 8.1 hours.

So, is the 8 hour thing a nominal measure like when we are told a download will take a certain amount of time at 56k?

A colleague has stated that the two very different machines will get the same amount of work done. I think that this is an impossibility.

I would like some clarification.

>>RSM
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Former Member
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Re: timing and work in Rice

We keep saying this. No matter, we will say it again: each work unit will complete as many structures as it can in 8 hours. Simple as that.
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Sekerob
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Re: timing and work in Rice

Mitch,

the Units of Data and the computation of credit is explained here:

http://www.worldcommunitygrid.org/forums/wcg/printpost?post=165595
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Richard Mitnick
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Re: timing and work in Rice

Thanks, I had not seen the other posts, now everything that I saw myself has been confirmed, esp 1000 vs 160 ns completed.



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